(a2+b2-c2+2ab)/(a2-b2+c2+2ac)=?

A    a+b+c

B    (a+b-c)/(a-b+c)

C    (a-b+c)/(a+b-c)

D    (a+b-c)/(a+b+c)

Solution

Correct Answer: Option B

(a2+b2-c2+2ab) / (a2-b2+c2+2ac)
= [(a + b)2 - c2] / [(a+c)2-b2]
= [(a + b + c) (a + b - c)] / [(a + b + c) (a - b + c)]
= (a + b - c)/(a - b + c)

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