(a²+b²-c²+2ab)/(a²-b²+c²+2ac)=?

A a+b+c

B (a+b-c)/(a-b+c)

C (a-b+c)/(a+b-c)

D (a+b-c)/(a+b+c)

Correct Answer: Option B

(a²+b²-c²+2ab) / (a²-b²+c²+2ac)
= [(a + b)² - c²] / [(a+c)²-b²]
= [(a + b + c) (a + b - c)] / [(a + b + c) (a - b + c)]
= (a + b - c)/(a - b + c)

(a2+b2-c2+2ab)/(a2-b2+c2+2ac)=?