LCM of two numbers is 1001 and their HCF is 13.If numbers are in the ratio of 7:11, then find the larger number?
Correct Answer: Option C
We know that, LCM × HCF = Product of numbers
Since the numbers are in a ratio 7 : 11,
Let the numbers be 7x and 11 x
∴ 7x × 11x= 1001 × 13
⇒ 77x2 = 1001 × 13
\(\Rightarrow \;{x^2}\; = \;\frac{{1001\; \times \;13}}{{77}}\)
⇒ x2 = 13 × 13
⇒ x = 13
So, the larger number = 11x = 11 × 13 = 143
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