50 g of an alloy of gold and silver contains 80% gold
(by weight). The quantity of gold, that is to be mixed
up with this alloy, so that it may contain 95% gold is?
(by weight). The quantity of gold, that is to be mixed
up with this alloy, so that it may contain 95% gold is?
Solution
Correct Answer: Option C
In 50 g alloy gold Quantity = 50 × 80/100
= 40 g
Suppose, In this mixture x g gold added
then,
(40+x)/(50+X)=95/100
⇒ 100 (40+ x) = 95 (50 + x)
⇒ 4000 + 100x = 4750 +95x
⇒ 100x - 95x = 4750-4000
⇒ 5x = 750
⇒ x = 150
so, 150 g gold added to the alloy.
= 40 g
Suppose, In this mixture x g gold added
then,
(40+x)/(50+X)=95/100
⇒ 100 (40+ x) = 95 (50 + x)
⇒ 4000 + 100x = 4750 +95x
⇒ 100x - 95x = 4750-4000
⇒ 5x = 750
⇒ x = 150
so, 150 g gold added to the alloy.
Practice More Questions on Our App!
Download our app for free and access thousands of MCQ questions with detailed solutions