4x2 - 3x - 1 = 0 সমীকরণের মূলদ্বয়ের অন্তর কত?
Solution
Correct Answer: Option B
দেওয়া আছে.
4x2 - 3x - 1 = 0
→ 4x2 - 4x + x - 1 = 0
⇒ 4x (x-1) + 1 (x - 1) = 0
⇒ (x - 1) (4x + 1) = 0
.: x - 1 = 0
অথবা 4x + 1 = 0
বা, 4x = -1
বা, x = -1/4
মূলদ্বয়ের অন্তর = 1-(-1/4)
= 1+1/4
= 5/4
4x2 - 3x - 1 = 0
→ 4x2 - 4x + x - 1 = 0
⇒ 4x (x-1) + 1 (x - 1) = 0
⇒ (x - 1) (4x + 1) = 0
.: x - 1 = 0
অথবা 4x + 1 = 0
বা, 4x = -1
বা, x = -1/4
মূলদ্বয়ের অন্তর = 1-(-1/4)
= 1+1/4
= 5/4
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