(লিখিত প্রশ্ন) Problem Solving (Show your Calculations / steps):
An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 36 times the difference between the two numbers. How many coins did the old man have?
An old man distributed all the gold coins he had to his two sons into two different numbers such that the difference between the squares of the two numbers is 36 times the difference between the two numbers. How many coins did the old man have?
Solution
Correct Answer: Option A
একজন বৃদ্ধের নিকট কিছু মুদ্রা ছিল যা তিনি তার দুই পুত্রের মধ্যে এমনভাবে ভাগ করে দিলেন যেন দুজনের প্রাপ্ত মুদ্রার সংখ্যার বর্গের পার্থক্য প্রাপ্ত মুদ্রার সংখ্যার পার্থক্যের 36 গুন। লোকটির নিকট কয়টি মুদ্রা ছিল?
Let, He gave x coins to first son.
& He gave y coins to second son.
According to question, x2 - y2 = 36 (x - y)
⇒ (x + y) (x - y) = 36 (x - y)
∴ x + y= 36
∴ The old man have 36 coins.
Let, He gave x coins to first son.
& He gave y coins to second son.
According to question, x2 - y2 = 36 (x - y)
⇒ (x + y) (x - y) = 36 (x - y)
∴ x + y= 36
∴ The old man have 36 coins.
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