x+2¹/³ +2 ²/³=0 হলে , x³+ 6 এর মান কত ?
Solution
Correct Answer: Option B
দেওয়া আছে,
x + 21/3 + 22/3 = 0
⇒ x = -(21/3 + 22/3) ........(1)
⇒ x3 = -(21/3 + 22/3)3
⇒ x3 = -{(21/3)}3+ {(22/3)}3 + 3.21/3.22/3(21/3 + 22/3)}
⇒ x3 = -{2 + 4 + 3.23/3(-x)} [(1) নং হতে]
⇒ x3 = -(6 - 6x)
⇒ x3 = -6 + 6x
∴ x3 + 6 = 6x
x + 21/3 + 22/3 = 0
⇒ x = -(21/3 + 22/3) ........(1)
⇒ x3 = -(21/3 + 22/3)3
⇒ x3 = -{(21/3)}3+ {(22/3)}3 + 3.21/3.22/3(21/3 + 22/3)}
⇒ x3 = -{2 + 4 + 3.23/3(-x)} [(1) নং হতে]
⇒ x3 = -(6 - 6x)
⇒ x3 = -6 + 6x
∴ x3 + 6 = 6x
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