x = √3+√2 হলে, x³+(1/x³)
Correct Answer: Option B
x = √3+√2
=> 1/x = 1/(√3+√2)
= (√3-√2)/(√3+√2)(√3-√2)
= (√3-√2)/{(√3)^2 - (√2)^2}
=> 1/x = √3-√2/3-2
1/x = √3-√2
x+1/x = √3+√2+√3-√2 = 2√3
এখন, x³+(1/x³) = (x+1/x)^3 -3.x.1/x (x+1/x)
= (2√3)^3 -3×2√3
= 8×3√3 -6√3
= 24√3 - 6√3
= 18√3
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