log2√6 + log2√(2/3) = ?
সমাধান
সঠিক উত্তর: Option B
log2√6 + log2√(2/3)
= log2√(2 × 3) + log2√2 - log2√3
= log2√2 + log2√3 + log2√2 - log2√3
= 2 log2√2
= log2(√2)2
= log22
= 1
= log2√(2 × 3) + log2√2 - log2√3
= log2√2 + log2√3 + log2√2 - log2√3
= 2 log2√2
= log2(√2)2
= log22
= 1
