Correct Answer: Option C

এখানে, BC=২০ মিটার, \[\angle ACB = {30^0}\]
মনে করি, AB=h
\[\begin{array}{l}
\tan {30^ \circ } = \frac{{AB}}{{BC}}\\
= > \frac{1}{{\sqrt 3 }} = \frac{h}{{20}}\\
= > h\sqrt 3 = 20\\
h = \frac{{20}}{{\sqrt 3 }}
\end{array}\]
Download our app for free and access thousands of MCQ questions with detailed solutions