The smallest of three consecutive even integers is 40 less than three times the largest. What is the largest of these integers?
Solution
Correct Answer: Option A
let the three numbers be a,b and c.. now,
The smallest of three consecutive even integers is 40 less than three times the largest means 3c-40=a.. 3c-a=40.. 2c+c-a=40.. c-a=4, as a,b,and c are consecutive even integers.. 2c+4=40.. 2c=36 or c=18.
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