If A, B, C and D are positive integers such that 4A = 9B, 17C = 11D, and 5C = 12A, then the arrangement of the four numbers from greatest to least is -

A CDAB

B BACD

C DCAB

D DCBA

E BDAC

Correct Answer: Option C

4A = 9B => B = 4/9 A

5C = 12A => C = 12/5 A

17C = 11D => D = 17/11 C = 17/11 (12/5 A) = 204/55 A

So the order from greatest to least is, 204/55 A, 12/5 A, A, 4/9 A

Nothing but, DCAB