x² - 4, x² + 4x + 4, x³ - 8 বীজগাণিতিক রাশির ল.সা.গু. কত?
Solution
Correct Answer: Option B
x² - 4 = (x + 2)(x - 2)
x² + 4x + 4 = (x + 2)²
x³ - 8 = (x)³ - (2)³ = (x - 2)(x² + 2x + 4)
∴ ল.সা.গু. = (x + 2)² (x - 2) (x² + 2x + 4) = (x + 2)² (x³ - 8)
x² + 4x + 4 = (x + 2)²
x³ - 8 = (x)³ - (2)³ = (x - 2)(x² + 2x + 4)
∴ ল.সা.গু. = (x + 2)² (x - 2) (x² + 2x + 4) = (x + 2)² (x³ - 8)
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