(x/3)+{4/(x+1)}=2 হলে, x এর মান কত?
Solution
Correct Answer: Option B
(x/3) + {4/(x+1)} = 2
⇒ [(x(x+1)) + (4 * 3)] / [3(x+1)] = 2
⇒ (x² + x + 12) / (3x + 3) = 2
⇒ x² + x + 12 = 6x + 6
⇒ x² + x - 6x + 12 - 6 = 0
⇒ x² - 5x + 6 = 0
⇒ x² - 3x - 2x + 6 = 0
⇒ (x - 2)(x - 3) = 0
∴ x এর দুটি সম্ভাব্য মান হল 2 এবং 3
⇒ [(x(x+1)) + (4 * 3)] / [3(x+1)] = 2
⇒ (x² + x + 12) / (3x + 3) = 2
⇒ x² + x + 12 = 6x + 6
⇒ x² + x - 6x + 12 - 6 = 0
⇒ x² - 5x + 6 = 0
⇒ x² - 3x - 2x + 6 = 0
⇒ (x - 2)(x - 3) = 0
∴ x এর দুটি সম্ভাব্য মান হল 2 এবং 3
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