log₂√6 + log₂√(2/3) = কত?
সমাধান
সঠিক উত্তর: Option C
log₂√6 + log₂√(2/3)
= log₂(√6 * √(2/3))
= log₂ √(6 * 2/3)
= log₂ √(12/3)
= log₂ √4
= log₂ 2
= 1
= log₂(√6 * √(2/3))
= log₂ √(6 * 2/3)
= log₂ √(12/3)
= log₂ √4
= log₂ 2
= 1
