1/4 - 1/6 + 1/9 - 2/7 + --- ধারাটির অসীম পদের সমষ্টি কত?
Solution
Correct Answer: Option B
এখানে প্রথম পদ a=1/4
সাধারণ অন্তর r= (-1/6) /(1/4) =-2/3
S∞= a/(1-r)
=(1/4)/ {1-(-2/3)}
=(1/4) / {1+(2/3)}
=(1/4)/(5/3)
=1/4 ×3/5
=3/20
সাধারণ অন্তর r= (-1/6) /(1/4) =-2/3
S∞= a/(1-r)
=(1/4)/ {1-(-2/3)}
=(1/4) / {1+(2/3)}
=(1/4)/(5/3)
=1/4 ×3/5
=3/20
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