∫(1/x2) dx এর মান কত ?
Solution
Correct Answer: Option A
∫(1/x2) dx = ∫x-2dx
= x-2+1/-2+1 + c
[যেহেতু,∫xndx = xn+1/n + 1 ]
= x-1/-1 + c
= - 1/x +c
= x-2+1/-2+1 + c
[যেহেতু,∫xndx = xn+1/n + 1 ]
= x-1/-1 + c
= - 1/x +c
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