Correct Answer: Option C
3/x + 4/(x+1)=2
=> {3(x+1) + 4x }/x(x+1) = 2
=> {3x + 3 + 4x} = 2 (x2+ x)
=> 7x + 3 = 2x2+ 2x
=> 2x2 - 5x - 3 = 0
=> 2x2 - 6x + x -3 =0
=> 2x(x-3) + 1(x-3) = 0
=> (2x +1) (x-3) = 0
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