Solution
Correct Answer: Option C
দেওয়া আছে, x+(1/x)=√3
⇒ {x+(1/x)}2=(√3)2
⇒ x2 + 2 . x . (1/x) + (1/x2) = 3
⇒ x2 + (1/x2) = 3 - 2 = 1
⇒ x2 + (1/x2) = 1
এখন, (x3+1/x3)
= (x)3 + (1/x)3
= {x + (1/x)} {x2 - x . (1/x) + (1/x)2}
= (√3) {x2 + (1/x2) - 1}
= (√3) (1 - 1)
= 0
বিকল্প সমাধানঃ
দেওয়া আছে, x+(1/x)=√3
এখন,
(x3+1/x3) = (x + 1/x)3 -3.x.1/x(x + 1/x)
=(√3)3 - 3√3
= 3√3 - 3√3
= 0