(xa-b )a+b . (xb-c )b+c . (xc-a )c+a = কত ?

(x^a-b)^a+b . (x^b-c)^b+c . (x^c-a)^c+a= কত ?

A 0

B 1

C 2

D 4

Correct Answer: Option B

(x^a-b)^a+b . (x^b-c)^b+c . (x^c-a)^c+a= x^{a²- b²} \( \times \) x^{b²- c²} \( \times \) x^{c²- a²} = x^{a²- b²+ b²- c² + c²- a²} = x⁰ = 1