\(\frac{{{2^{x + 4\;}} - {{4.2}^{x + 1}}}}{{{2^{x + 4}} \div 2}}\) এর মান কত ? 

A

B

C

D 16 

Solution

Correct Answer: Option B

\(\frac{{{2^{x\;}}{{.2}^{4\;}} - {\rm{ }}{2^{2\;}}{{.2}^{x + 1\;}}}}{{{2^{x\;}}\;{{.2}^{4\;}} \div 2}}\) 

= \(\frac{{{2^{x\;}}{{.2}^{4\;}} - {\rm{ }}{2^{2\;}}{{.2}^{x + 1\;}}}}{{{2^{x\;}}\;{{.2}^{4\;}} \div 2}}\) 

= \(\frac{{{2^{x\;}}{{.2}^{4\;}} - {\rm{ }}{2^{2 + x + 1\;}}}}{{{2^{x\;}}\;{{.2}^{4\;}} \div 2}}\) 

= \(\frac{{{2^{x\;}}{{.2}^{4\;}} - {2^{3 + x\;}}}}{{{2^{x\;}}{{.2}^{2 - 1}}}} \)

= \(\frac{{{2^{x\;}}({2^{4\;}} - {2^3})}}{{{2^{x\;}}.2}} \)

= \(\frac{{16 - 8}}{2} \)

= \(\frac{8}{2}\) 

= 4 

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