log2 \(\sqrt 6 \)+ log2 \(\sqrt {\frac{2}{3}} \) = কত ?

log₂ \(\sqrt 6 \)+ log₂ \(\sqrt {\frac{2}{3}} \) = কত ?

A log5

B 1

C log2²

D 3log2

Correct Answer: Option B

log₂ \(\sqrt 6 \)+ log₂ \(\sqrt {\frac{2}{3}} \) =

log₂ \((\sqrt {6 \times \frac{2}{3}} )\) = log₂ \((\sqrt 2 \times \sqrt 2 )\) = log₂ 2 = 1