log2 \(\sqrt 6 \)+ log2 \(\sqrt {\frac{2}{3}} \) = কত ?
Correct Answer: Option B
log2 \(\sqrt 6 \)+ log2 \(\sqrt {\frac{2}{3}} \) =
log2 \((\sqrt {6 \times \frac{2}{3}} )\) = log2 \((\sqrt 2 \times \sqrt 2 )\) = log2 2 = 1
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