\(\frac{3}{x} + \frac{4}{{x + 1}}\) = 2 হলে, x এর মান-  

A

B

C

D

Solution

Correct Answer: Option C

\(\frac{3}{x} + \frac{4}{{x + 1}} = 2\) 

বা, \(\frac{3}{x} + \frac{4}{{x + 1}} = 2\) 

বা, \(\frac{{3(x + 1) + 4x}}{{x(x + 1)}} = 2\) 

বা, \(\frac{{3x + 3 + 4x}}{{{x^{2\;}} + x}} = 2\) 

বা, 2x+2x=7x+3 

বা, 2x+2x-7x-3 = 0 

বা, 2x-5x-3 = 0  

বা, 2x-6x+x-3 = 0 

বা, 2x(x-3)+1(x-3) = 0 

বা, (x-3)(2x+1) = 0 

 x-3 = 0  অথবা   2x+1 = 0 

 x =3     অথবা   2x= -1        x = \( - \frac{1}{2}\)  

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