\(\frac{{x - a}}{{{a^2} - \;{b^2}}} = \frac{{x - b}}{{\;{b^2}

\(\frac{{x - a}}{{{a^2} - \;{b^2}}} = \frac{{x - b}}{{\;{b^2} - {a^{2\;}}}}\) হলে x = ?

A \(\frac{{a - b}}{2}\)

B \(\frac{{b - a}}{2}\)

C \(\frac{{a + b}}{2}\)

D a+b

Correct Answer: Option C

\(\frac{{x - a}}{{\;{a^2} - {b^2}}} = - \frac{{x - b}}{{({a^2} - {b^2})}}\) = x-a = -x+b =2x = a+b x = \(\frac{{a + b}}{2}\)