\(\frac{3}{{y + 1}} = \frac{4}{{y - 2}}\) সমীকরণে y এর মান কত ?  

A -10 

B \(\frac{3}{4}\) 

C \(\frac{4}{3}\) 

D 10 

Solution

Correct Answer: Option A

\(\frac{3}{{y + 1}} = \frac{4}{{y - 2}}\)  বা, 4y+4 = 3y - 6   বা, y = -10  

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