P is now 8 years older than Q. 17 years ago P was twice as old as Q. How old will Q be in 10 years?
Correct Answer: Option D
Let, present age of Q=x
and present age of P = x+8
17 years ago,
Q’s age=(x-17) and P’s age=(x+8-17)
According to the question,
(x+8-17)=2(x-17)
=> 2x-x=34-9
=> x=25
So, After 10 years Q’s age will be (25+10)=35 years
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