P is now 8 years older than Q. 17 years ago P was twice as old as Q. How old will Q be in 10 years?

A    30

B    23

C    25

D    35

Solution

Correct Answer: Option D

 

Let, present age of Q=x

 and present age of P = x+8

17 years ago,

Q’s age=(x-17) and P’s age=(x+8-17)

According to the question,

(x+8-17)=2(x-17)

=> 2x-x=34-9

=> x=25

So, After 10 years Q’s age will be (25+10)=35 years

 

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