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    How many different six-digit numbers can be formed using all of the following digits: 3, 3, 4, 4, 4, 5?

A    25

B    40

C    50

D    60

Solution

Correct Answer: Option D

 

Total = 6!2!3!=6×5×4×3×2×12×1×3×2×1=60

 

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