How many different six-digit numbers can be formed using all of the following digits: 3, 3, 4, 4, 4, 5?
Correct Answer: Option D
Total = \(\frac{{6!}}{{2!3!}} = \frac{{6 \times 5 \times 4 \times 3 \times 2 \times 1}}{{2 \times 1 \times 3 \times 2 \times 1}} = 60\)
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