How many different six-digit numbers can be formed using all of the following digits: 3, 3, 4, 4, 4, 5?

A 25

B 40

C 50

D 60

Correct Answer: Option D

Total = $\frac{{6!}}{{2!3!}} = \frac{{6 \times 5 \times 4 \times 3 \times 2 \times 1}}{{2 \times 1 \times 3 \times 2 \times 1}} = 60$