How many 3-digit numbers can be formed the digits 2, 3, 4, 5, 6,7 and 9, which are divisible by 5 and none of the digits is repeated?

A    5

B    10

C    15

D    20

Solution

Correct Answer: Option D

 

As the 3 digit number must be a multiple of 5, it must have 5 in its units place

Ex: xy5. X and Y can be any of the remaining 5 digits(2,3,6,7,9).

These remaining 5 digits can have 5p2 permutations ( P- because the arrangement is important). 5p2 =20.

That gives 20 possible arrangements of the 5 digits. 

 

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