Nice pieces of paper numbered consecutively from 1 to 9 are put into a box. If a piece of paper is drawn at random from the box, what is the probability that it will have a number greater than 6 ?

A \(\frac{1}{9}\)

B \(\frac{1}{3}\)

C \(\frac{2}{9}\)

D \(\frac{5}{9}\)

Correct Answer: Option B

Numbers greater than 6 = 7, 8,9 = 3টি Probability = \(\frac{3}{9} = \frac{1}{3}\)