Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?

A 0.45

B 0.4

C 0.25

D 0.5

Correct Answer: Option A

Here, Total results S = {1,2,3,4,....,19,20}

Let E = event of getting a multiple of 3 or 5 = {3,6,9,12,15,18,5,10,20}

P(E) = \(\frac{{n(E)}}{{n(S)}} = \frac{9}{{20}} = \frac{{4.5}}{{10}} = 0.45\)