\(\frac{1}{{\sqrt 2 }},1,\sqrt 2 \) --------- ধারাটির কোন পদ \(8\sqrt 2 \) হবে?
Solution
Correct Answer: Option A
শর্তমতে, aq = \(8\sqrt 2 \)
বা, \(\frac{1}{{\sqrt 2 }}.{(\sqrt 2 )^{n - 1\;}} = {2^{3\;}}\sqrt 2 \)
বা, \({(\sqrt 2 )^{ - 1\;}} \times {(\sqrt 2 )^{n - 1\;}} = {(\sqrt 2 )^{6\;}}.\sqrt 2 \)
বা, \({(\sqrt 2 )^{n - 2}} = {(\sqrt 2 )^{7\;}}\)
বা, n - 2 = 7
n = 9
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