\(\frac{{{2^{n + 1\;}}{{.3}^{2n + m}}{{.5}^{m + n}}{{.6}^m}}}{{\;{6^n}{{.10}^{m + 2}}{{.15}^n}}}\)

\(\frac{{{2^{n + 1\;}}{{.3}^{2n + m}}{{.5}^{m + n}}{{.6}^m}}}{{\;{6^n}{{.10}^{m + 2}}{{.15}^n}}}\)

A \(\frac{1}{{30}}\)

B \(\frac{1}{{40}}\)

C \(\frac{1}{{50}}\)

D \(\frac{1}{{60}}\)

Solution

Correct Answer: Option C