log2√1⁄6 + log2√3⁄2=কত?
Solution
Correct Answer: Option C
log2√1⁄6 + log2√3⁄2
=log2 (1⁄√3√2* √3⁄√2)
=log2½
=log22-1
=-1log22
=-1*1=-1
=log2 (1⁄√3√2* √3⁄√2)
=log2½
=log22-1
=-1log22
=-1*1=-1
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