log2√1⁄6 + log2√3⁄2=কত?

log₂√1⁄6 + log₂√3⁄2=কত?

A 3

B 2

C -1

Solution

Correct Answer: Option C

log₂√1⁄6 + log_2^√3⁄2
=log₂ (1⁄√3√2* √3⁄√2)
=log₂^½=log₂^{2^-1}=-1log₂²=-1*1=-1