2x2 + x এবং 4x2 - 1 এর ল.সা.গু কত?

A x (2x2 + 1)

B x2 (2x2 + 1)

C (2x2 + 1)

D x (2x + 1) (2x - 1)

Solution

Correct Answer: Option D

দেওয়া আছে,
2x2 + x = x(2x + 1)
এবং,
4x2 - 1 = (2x)2 - (1)2
= (2x + 1) (2x - 1)

∴ নির্ণেয় ল.সা.গু = x (2x + 1) (2x - 1)

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