প্রদত্ত সমীকরণের জন্য প্রশ্নবোধক স্থানে কত বসবে?
[(?)2/3]/42 = 5/(?)1/3
Solution
Correct Answer: Option D
[(?)2/3]/42 = 5/(?)1/3
= [(x)2/3]/42 = 5/(x)1/3
⇒ x2/3 × x1/3 = 42 × 5
⇒ x2/3 +1/3 = 210
⇒ x3/3 = 210
x = 210
= [(x)2/3]/42 = 5/(x)1/3
⇒ x2/3 × x1/3 = 42 × 5
⇒ x2/3 +1/3 = 210
⇒ x3/3 = 210
x = 210
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