প্রদত্ত সমীকরণের জন্য প্রশ্নবোধক স্থানে কত বসবে?

[(?)2/3]/42 = 5/(?)1/3

A 10

B 10√2

C √20

D 210

Solution

Correct Answer: Option D

[(?)2/3]/42 = 5/(?)1/3
= [(x)2/3]/42 = 5/(x)1/3
⇒ x2/3 × x1/3 = 42 × 5
⇒ x2/3 +1/3 = 210
⇒ x3/3 = 210
x = 210

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