{(xp/xq)p+q} {(xq/xr)q+r} {(xr/xp)r+p} = কত?

{(x^p/x^q)^p+q} {(x^q/x^r)^q+r} {(x^r/x^p)^r+p} = কত?

A x

B x^p+q+r

C x^2p+2q+2r

D 1

Solution

Correct Answer: Option D

(x^p/x^q)^{p + q} . (x^q/x^r)^{q + r}. (x^r/x^p)^{r + p}
= (x^{p - q})^{p + q}. (x^q -^r)^{q + r} . (x^{r -}^p)^{r + p}= x^{(p - q)(p + q)}. x^{(q - r)(q + r)} . x^{(r - p)(r + p)}₌_xp² - q² . _xq² - r²._xr² - p²
₌_xp² - q²+ q² - r²+r² - p²
= x^{0
= 1}

Solution

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