Loading [MathJax]/extensions/tex2jax.js
 
{(xp/xq)p+q} {(xq/xr)q+r} {(xr/xp)r+p} = কত?

A x

B xp+q+r

C x2p+2q+2r

D 1

Solution

Correct Answer: Option D

(xp/xq)p + q . (xq/xr)q + r. (xr/xp)r + p 
= (xp - q)p + q. (xq - r)q + r . (xr - p)r + p
= x(p - q)(p + q). x(q - r)(q + r) . x(r - p)(r + p)
=xp2 - q2 . xq2 - r2.xr2 - p2 
=xp2 - q+ q2 - r2+r2 - p2
= x0
= 1

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