How many terms are there in 20, 25, 30......... 140?
Solution
Correct Answer: Option D
Number of terms = {(last term - 1st term)/common difference}+1
= (140−20)/5 + 1
= (120/5) + 1
= 24 + 1
= 25.
= (140−20)/5 + 1
= (120/5) + 1
= 24 + 1
= 25.
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