[{(a2 + b2)/2ab} - 1] ÷ [{(a3 - b3)/(a - b)} - 3ab] = কত?
সমাধান
সঠিক উত্তর: Option C
[{(a2 + b2- 2ab)/2ab} ÷ [{a3 - b3- 3ab(a - b)}/(a - b)]
[(a - b)2/2ab]÷ [{(a - b)3}/(a - b)]
[(a - b)2/2ab] ×[(a - b)/(a - b)3]
= 1/2ab
[(a - b)2/2ab]÷ [{(a - b)3}/(a - b)]
[(a - b)2/2ab] ×[(a - b)/(a - b)3]
= 1/2ab
