A ও B দুটি সসীম সেট। যদি n(A) = 20, n(B) = 28 এবং n(A ∪ B) = 36 হয়, তাহলে n(A ∩ B) =?
Solution
Correct Answer: Option D
আমরা জানি,
n(A ∪ B) = n(A) + n(B) - n(A ∩ B).
∴ n(A ∩ B) = n(A) + n(B) - n(A ∪ B)
= 20 + 28 - 36
= 48 - 36
= 12
n(A ∪ B) = n(A) + n(B) - n(A ∩ B).
∴ n(A ∩ B) = n(A) + n(B) - n(A ∪ B)
= 20 + 28 - 36
= 48 - 36
= 12
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