If 3x < 2y < 0, which of the following must be the greatest?

A 2y - 3x

B 3x - 2y

C -(3x - 2y)

D - (3x + 2y)

E 0

Correct Answer: Option D

Solution:

যেহেতু, 3x < 2y < 0, তাই ধরি, x = y = -1;

অপশন a) এর 2y - 3x = [ 2 \( \times \) (-1) ] - [ 3 \( \times \) (-1) ] = 1

অপশন b) এর 3x - 2y = [ 3 \( \times \) (-1) ] - [ 2 \( \times \) (-1) ] = -1

অপশন c) এর - (3x - 2y) = - [ 3 \( \times \) (-1) - 2 \( \times \) (-1) ] = 1

অপশন d) এর - (3x + 2y) = - [ 3 \( \times \) (-1) ] + [ 2 \( \times \) (-1) ] = 15