The average (arithmetic mean) of 4 different integers is 75 . If the largest integer is 90, What is the least possible value of the smallest integer?
Solution
Correct Answer: Option D
Solution:
the sum of the four different numbers is 75 * 4 = 300, the largest one is 90, so the sum of the rest three numbers is 300-90 = 210, the average of them is 210/3 = 70. Since the 4 numbers are different, the second largest and third largest should be 89,88. Hence, the least number is 70- ( (89-70) + (88 - 70 )) = 70 - 37 = 33.
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