x+y=3, x-y=1 হলে x²+y² এর মান কত?
Solution
Correct Answer: Option D
2(x²+y²) = (x+y)²+(x-y)²
= 3²+ 1²
= 9+1
2(x²+y²)= 10
∴ x²+y² = 10/2
=5
= 3²+ 1²
= 9+1
2(x²+y²)= 10
∴ x²+y² = 10/2
=5
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