(a2+b2-c2+2ab)/(a2-b2+c2+2ac) =কত?
 

A a+b+c

B (a+b-c)/(a-b+c)

C (a-b+c)/(a+b-c)

D (a+b-c)/(a+b+c)

Solution

Correct Answer: Option B

(a2+b2-c2+2ab)/(a2-b2+c2+2ac)
={(a+b)2 - (c)2}/{(a+c)2-(b)2}
={(a+b+c)(a+b-c)}/{(a+b+c)(a-b+c)}
=(a+b-c)/(a-b+c)


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