x+y=2 , x3+y3+6xy=?
Solution
Correct Answer: Option C
x3+y3+6xy=x3+y3+3×2×xy
=x3+y3+3(x+y).xy [x+y=2]
=x3+y3+3xy(x+y)
=(x+y)3
=(2)3
=8
=x3+y3+3(x+y).xy [x+y=2]
=x3+y3+3xy(x+y)
=(x+y)3
=(2)3
=8
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