f(x) = x³ + 8 হলে, f(-2) + f(0) এর মান কত?
Solution
Correct Answer: Option B
প্রদত্ত ফাংশন, f(x) = x³ + 8
f(-2) = (-2)³ + 8 = - 8 + 8 = 0
f(0) = (0)³ + 8 = 8
∴ f(-2) + f(0) = 0 + 8 = 8
f(-2) = (-2)³ + 8 = - 8 + 8 = 0
f(0) = (0)³ + 8 = 8
∴ f(-2) + f(0) = 0 + 8 = 8
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