sin(9π/2 + θ) = ?
Solution
Correct Answer: Option A
প্রথমে 9π/2 কোণটিকে 2π এর গুণিতকে বিভাজন করি —
9π/2 = 8π/2 + π/2 = 4π + π/2
এখন, আমরা জানি
sin(2nπ + α) = sinα
অতএব,
sin(9π/2 + θ) = sin(4π + π/2 + θ)
= sin(π/2 + θ) [কারণ sin(4π + α) = sinα]
এখন সূত্র অনুযায়ী,
sin(π/2 + θ) = cosθ
অতএব, sin(9π/2 + θ) = cosθ
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