If m is an integer such that (-2)2m=29-m then m=?

If m is an integer such that (-2)^2m=2^9-m then m=?

A 1

B 2

C 3

D 4

Correct Answer: Option C

(-2)^2m = 2^{9 - m}
⇒ ((-2)²)^m = 2^{9 - m}
⇒ (2)^2m = 2^{9 - m}
⇒ 2m = 9 - m
⇒ 3m = 9
⇒ m = 3