√2/(√6+2)=√2/{(√3×√2)+(√2×√2)} =√2/{√2 (√3+√2)}=1/(√3+√2) =1(√3+√2)/{(√3+√2)(√3-√2)} [লব ও হরকে (√3-√2) দ্বারা ভাগ করে ] (√3-√2)/{(√3)2-(√2)2}=(√3-√2)/(3-2)=(√3-√2)/1=√3-√2
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